From 8eb0d254da84811b26df92f582ac7c4082c4b701 Mon Sep 17 00:00:00 2001
From: Sebastiaan Janssen <sebastiaan@umbraco.com>
Date: Sun, 21 May 2017 13:35:29 +0200
Subject: [PATCH] U4-9940 Make it easy to get the integer Id of an item from
 it's Udi

---
 src/Umbraco.Web/Extensions/UdiExtensions.cs | 24 ++++++++++++++++++++-
 1 file changed, 23 insertions(+), 1 deletion(-)

diff --git a/src/Umbraco.Web/Extensions/UdiExtensions.cs b/src/Umbraco.Web/Extensions/UdiExtensions.cs
index c814d63b8c..9b07359ee8 100644
--- a/src/Umbraco.Web/Extensions/UdiExtensions.cs
+++ b/src/Umbraco.Web/Extensions/UdiExtensions.cs
@@ -36,8 +36,30 @@ namespace Umbraco.Web.Extensions
                         return umbracoHelper.TypedMember(memberAttempt.Result);
                     break;
             }
-            
+
             return null;
         }
+
+        /// <summary>
+        /// An extension method to easily acquire the integer Id for a given udi
+        /// </summary>
+        /// <param name="udi"></param>
+        /// <returns>An <see cref="int"/> identifier if the item is found, -1 otherwise</returns>
+        public static int ToIntId(this Udi udi)
+        {
+            Udi identifier;
+            if (Udi.TryParse(udi.ToString(), out identifier) == false)
+                return -1;
+
+            var guidUdi = GuidUdi.Parse(udi.ToString());
+            var umbracoType = Constants.UdiEntityType.ToUmbracoObjectType(identifier.EntityType);
+
+            var entityService = ApplicationContext.Current.Services.EntityService;
+            var entity = entityService.GetByKey(guidUdi.Guid, umbracoType);
+            if (entity == null)
+                return -1;
+
+            return entity.Id;
+        }
     }
 }